A particle moving in a straight line has, magnitude of velocity $v$ given by $v^{2} = 12 - 3 x^{2}$ , where $v$ is in m/s and $x$ is in m. The amplitude of the oscillation of the particle is (in m)

1 m

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2 m

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4 m

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12 m

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Solution

The correct option is B 2 m
expression of velocity in S.H.M
$v^{2} = 12 - 3 x^{2}$
$v^{2} = 3 (4 - x^{2})$
$v^{2} = ω^{2} (A^{2} - x^{2})$
$A = 2 m$

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A particle moving in a straight line has, magnitude of velocity v given by v2=12−3x2, where v is in m/s and x is in m. The amplitude of the oscillation of the particle is (in m)

The correct option is B 2 mexpression of velocity in S.H.Mv2=12−3x2v2=3(4−x2)v2=ω2(A2−x2)A=2m

A particle moving in a straight line has, magnitude of velocity $v$ given by $v^{2} = 12 - 3 x^{2}$ , where $v$ is in m/s and $x$ is in m. The amplitude of the oscillation of the particle is (in m)

The correct option is B 2 m
expression of velocity in S.H.M
$v^{2} = 12 - 3 x^{2}$
$v^{2} = 3 (4 - x^{2})$
$v^{2} = ω^{2} (A^{2} - x^{2})$
$A = 2 m$