You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Velocity Displacement Relationship

A particle mo...

Question

A particle moving in a straight line has, magnitude of velocity $v$ given by $v^{2} = 12 - 3 x^{2}$ , where $v$ is in m/s and $x$ is in m. The amplitude of the oscillation of the particle is (in m)

1 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2 m
expression of velocity in S.H.M
$v^{2} = 12 - 3 x^{2}$
$v^{2} = 3 (4 - x^{2})$
$v^{2} = ω^{2} (A^{2} - x^{2})$
$A = 2 m$

Suggest Corrections

Similar questions

A particle moving in a straight line has velocity and displacement equation as V = 4 $\sqrt{1 + S}$ , where V in m/s and s is in m.

The initial velocity of the particle in m/s is ______

Q. The velocity of a particle moving on the x-axis is given by

v = x^{2} + x

where v in m/s and x is in m. Its acceleration in

m / s^{2}

when passing through the point x=2m.

Q. Velocity

(V)

versus displacement

(S)

graph of a particle moving in a straight line is as shown in the figure. Given

V_{0} = 4 m / s

and

S_{o} = 20 m .

S = 30 m

, what is the acceleration of particle?

Q. A particle is moving in straight line. The velocity v of the particle varies with time t as

v = t^{2} - 4 t

. then the distance traveled by the particle in

t = 0

t = 6 s

(where $t$ in second and v is in m/s )

Velocity-time equation of a particle moving in a straight line is v = 2t - 4 for t ≤ 2 s and v = 4-2t for t> 2 s. The distance travelled by the particle in the time interval from t = 0 to t = 4 s is (Here, t is in second and v in m/s)

Join BYJU'S Learning Program

A particle moving in a straight line has, magnitude of velocity v given by v2=12−3x2, where v is in m/s and x is in m. The amplitude of the oscillation of the particle is (in m)

The correct option is B 2 mexpression of velocity in S.H.Mv2=12−3x2v2=3(4−x2)v2=ω2(A2−x2)A=2m

A particle moving in a straight line has, magnitude of velocity $v$ given by $v^{2} = 12 - 3 x^{2}$ , where $v$ is in m/s and $x$ is in m. The amplitude of the oscillation of the particle is (in m)

The correct option is B 2 m
expression of velocity in S.H.M
$v^{2} = 12 - 3 x^{2}$
$v^{2} = 3 (4 - x^{2})$
$v^{2} = ω^{2} (A^{2} - x^{2})$
$A = 2 m$