A particle moving in one-dimension with constant acceleration of $10 m / s^{2}$ is observed to cover a distance of 100m during a 4s interval. How far will the particle move in the next 4s?

Open in App

Solution

Given : $a = 10 m / s^{2}$
Let the initial velocity be $u$ .
Using $S = u t + \frac{1}{2} a t^{2}$
For first $4 s$ , $S = 100 m$
Or $100 = u \times 4 + \frac{1}{2} \times 10 \times 4^{2}$
$⟹ u = 5 m / s$
Distance covered in $8 s$ , $S_{t o t a l} = 5 \times 8 + \frac{1}{2} \times 10 \times 8^{2} = 360 m$
Distance covered in last 4 seconds, $D = 360 - 100 = 260 m$

Suggest Corrections

Similar questions

A body starts moving with an initial velocity 50 m/s and acceleration 20 $m / s^{2}$ . How much distance it will cover in 4s ? Also, calculate its average speed during this time interval.

Q. A particle starts from rest and moves in a circular motion with constant angular acceleration of

2 r a d / s^{2}

. Find
a. Angular velocity
b. Angular displacement of the particle after

4 s

c. The number of revolutions completed by the particle during these

4 s

.
d. If the radius of the circle is

10 c m

, find the magnitude and direction of net acceleration of the particle at the end of

4 s

Q. The velocity of a body moving with a uniform acceleration of

2 m / s^{2}

10 m / s

.Its velocity after an interval of

4 s

Q. A particle, initially at rest, moves with an acceleration

5 m s^{- 2}

for

5 s

. Find the distance travelled in

4 s

Q. Starting from rest a particle moves in a straight line with acceleration

a = [2 + | t - 2 |] m / s^{2}

What will be the velocity(in

m / s

) of particle at the end of

4 s

Join BYJU'S Learning Program

A particle moving in one-dimension with constant acceleration of 10m/s2 is observed to cover a distance of 100m during a 4s interval. How far will the particle move in the next 4s?

Given : a=10m/s2 Let the initial velocity be u.Using S=ut+12at2For first 4 s, S=100 mOr 100=u×4+12×10×42⟹ u=5 m/sDistance covered in 8 s, Stotal=5×8+12×10×82=360 mDistance covered in last 4 seconds, D=360−100=260 m

A particle moving in one-dimension with constant acceleration of $10 m / s^{2}$ is observed to cover a distance of 100m during a 4s interval. How far will the particle move in the next 4s?