A particle moving on x-axis has potential energy U=2−20x+5x2 Joule along x-axis. The particle is released at r=−3. The maximum value of x will be (x is in meter):
A
5m
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B
3m
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C
7m
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D
8m
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Solution
The correct option is D7m F=−dUdx=20−10x F=0 at x=0 So, from x=−3 to x=2, amplitude is 5. Hence other extreme position will be x=2+5=7