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Question
A particle moving with a velocity →v=2^i+3^j−4^k strikes a smooth fixed wall placed in x-y plane. Assuming the collision to be inelastic, the velocity of the particle just after the collision may be
A particle moving with a velocity →v=2^i+3^j−4^k strikes a smooth fixed wall placed in x-y plane. Assuming the collision to be inelastic, the velocity of the particle just after the collision may be
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Solution
The correct option is A 2^i+3^j+3^k
As a result of collision of the particle with the wall, the component of velocity (z-component) normal to the wall is changed. The z-component of velocity reverses in direction with lesser magnitude due to inelastic nature of collision.
Hence 2^i+3^j+3^k is the only possible answer.
As a result of collision of the particle with the wall, the component of velocity (z-component) normal to the wall is changed. The z-component of velocity reverses in direction with lesser magnitude due to inelastic nature of collision.
Hence 2^i+3^j+3^k is the only possible answer.
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