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Question

A particle moving with certain velocity collides elastically with another particle at rest. If it were head on collision, the K.E. transferred by the colliding particle is 100% when its mass is equal to the

A
the mass of the stationary particle
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B
twice the mass of the stationary particle
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C
half the mass of the stationary particle
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D
1/4 times the mass of the stationary particle
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Solution

The correct option is A the mass of the stationary particle
We know that during perfectly elastic collision the momentum and kinetic energy both are conserved .
Here it is given that 100% kinetic energy is trasferred . Therefore it is an perfectly elastic collision. Now we have
M1 V1 = M2 V2 ----------(1)
1/2 M1 (V1)^2 = 1/2 M2 (V2)^2----------(2)\
So by solving 1 and 2 we can conclude M1 = M2

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