A particle moving with kinetic energy = 3J makes an elastic headon collision with a stationary particle which has twice its mass. During the impact.
In a headon elastic collision between two particles, the kinetic energy becomes minimum andthe potential energy becomes maximum at the instant when the two move with a common velocity.
The momentum and the total energy are conserved at every instant.
Let m and u be the mass and initial velocity respectively of the first particle, 2m, be the mass of the second particle, and v be the common velocity.
Then, 12mu2=3J;mu=(m+2m)vorv=u3
∴ The minimum KE of the system =13(3m)(u3)2=(12mu2)13=1J
∴ The maximum PE of the system = 2J