A particle obeys the following $v - t$ graphs as shown. The average velocity over $30 s$ is:

10 m / s

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5 m / s

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\frac{10}{3} m / s

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Zero

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Solution

The correct option is B $5 m / s$
Average velocity over $30 s e c s = \frac{T o t a l d i s t a n c e c o v e r e d i n 30 s e c s}{T o t a l t i m e}$
$= \frac{A r e a r v e l e r t h e v - t g r a p h}{T o t a l t i m e}$
$= \frac{\frac{1}{2} \times 30 \times 10}{30}$
$= 5 m / s$

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