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Standard XII

Physics

How to Visualize Electric Fields

A particle of...

Question

A particle of charge $1 μ C$ and mass 1 gm moving with a velocity of $4 m / s$ is subjected to a uniform electric field of magnitude $300 V / m$ for 10 sec in the direction of velocity. Then it's final speed can be approximated to :

7 m / s

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4 m / s

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3 m / s

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6 m / s

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Solution

The correct option is A $7 m / s$
Here, $m a = q E \Rightarrow a = \frac{q E}{m} = \frac{10^{- 6} \times 300}{0.001} = 0.3 m / s^{2}$
By using, $v = u + a t$ , we will get, $v = 4 + 0.3 \times 10 = 7 m / s$

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A particle of charge 1μC and mass 1 gm moving with a velocity of 4m/s is subjected to a uniform electric field of magnitude 300V/m for 10 sec in the direction of velocity. Then it's final speed can be approximated to :

The correct option is A 7m/sHere, ma=qE⇒a=qEm=10−6×3000.001=0.3m/s2By using, v=u+at, we will get, v=4+0.3×10=7m/s

A particle of charge $1 μ C$ and mass 1 gm moving with a velocity of $4 m / s$ is subjected to a uniform electric field of magnitude $300 V / m$ for 10 sec in the direction of velocity. Then it's final speed can be approximated to :

The correct option is A $7 m / s$
Here, $m a = q E \Rightarrow a = \frac{q E}{m} = \frac{10^{- 6} \times 300}{0.001} = 0.3 m / s^{2}$
By using, $v = u + a t$ , we will get, $v = 4 + 0.3 \times 10 = 7 m / s$