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Standard XII

Physics

Conservative and Non-Conservative Forces

A particle of...

Question

A particle of charge $q$ and mass $m$ starts moving from origin under the action of an electric field $\to E$ = $E_{0} \to i$ and magnetic field $\to B$ = $B_{0} \to k$ . Its velocity at $(x, 3, 0)$ is $(4 i + 3 i)$ , the value of $x$ is:

\frac{36 E_{o} B_{0}}{q m}

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\frac{25 m}{2 q E_{0}}

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\frac{10 m}{q E_{o}}

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\frac{25 E_{0} B_{0}}{m}

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Solution

The correct option is B $\frac{25 m}{2 q E_{0}}$
$\begin{matrix} (q ε_{0}) x = \frac{1}{2} m v^{2} \Rightarrow q ε_{0} x = \frac{25 m}{2} x = \frac{25}{2 q ε_{0}} H e n c e, o p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$

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