A particle of charge -q & mass m moves in a circular orbit about a fixed charge +Q in a circle of radius r and time period T. which of the following may be correct
A
r3αT2
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B
r2αT3/2
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C
r3αT2/3
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D
None of these
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Solution
The correct option is Cr3αT2/3 Charge =−q
mass =m
fixed charge =+Q
radius =r
Time period =T
according to Kepler's celestial body law, we get that,
r3αT2/3
The square of the orbital period of a planet is directly proportional to the cube the semi - major axis of its orbit.
(2) A line segment joining a planet and the sun sweeps out equal areas during equal intervals of time.
Kepler's third law provides an accurate description of the period and distance for a planet's orbitals about the sun. Additionally, the same law that describe that T2/R3 ratio for planet's orbitals about the sun also accurately describes the T2/R3 ratio for any satellite.
⇒ Then, the ratio of the squares of the periods of any two planets is equal to the ratio of the cubes of their average distances from the sun. (The law of harmonics).