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Standard XII

Physics

Net Force

A particle of...

Question

A particle of mass 0.1 kg has an initial speed of 4ms $^{- 1}$ at a point on a rough horizontal road. The coefficient of friction between the object and road is 0.15 the particle moves to a point B at a distance of 2m from A. What is the speed of particle at B? Take g=10 $m s^{- 2}$

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Solution

m=0.1kg
$V_{i n i t i a l} = u = 4 ㎧ μ = 0.15 s = 2 m v_{f i n a l} = v v^{2} = u^{2} - 2 a s v^{2} = 16 - 2 \times 0.15 \times 10 \times 2 = 10 v = \sqrt{10 m}$

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A particle of mass 0.1 kg has an initial speed of 4ms−1 at a point on a rough horizontal road. The coefficient of friction between the object and road is 0.15 the particle moves to a point B at a distance of 2m from A. What is the speed of particle at B? Take g=10 ms−2

m=0.1kgVinitial=u=4㎧μ=0.15s=2mvfinal=vv2=u2−2asv2=16−2×0.15×10×2=10v=√10m

A particle of mass 0.1 kg has an initial speed of 4ms $^{- 1}$ at a point on a rough horizontal road. The coefficient of friction between the object and road is 0.15 the particle moves to a point B at a distance of 2m from A. What is the speed of particle at B? Take g=10 $m s^{- 2}$

m=0.1kg
$V_{i n i t i a l} = u = 4 ㎧ μ = 0.15 s = 2 m v_{f i n a l} = v v^{2} = u^{2} - 2 a s v^{2} = 16 - 2 \times 0.15 \times 10 \times 2 = 10 v = \sqrt{10 m}$