Question

A particle of mass 0.10 kg executes Simple harmonic motion with an amplitude 0.05 m and frequency 20 vib/s. Its energy of oscillation is

• A. 2 J
• B. 4 J
• C. 1 J
• D. zero

Answer 1

Answer: (A)

2 J

$E=\frac{1}{2}m{\omega }^2{A}^2$

$=\frac{1}{2}\times 10\times {\left(2\pi \times 20\right)}^2\times {\left(0.05\right)}^2$

$=2J$

Hence,

option $\left(A\right)$ is correct answer.