A particle of mass 0.2kg is moving in one dimension under a force that delivers a constant power of 0.5W to the particle. If the initial speed (in ms−1) of the particle is zero, then the speed (in ms−1) of the particle after 5s is:
A
8
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B
5
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C
15
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D
25
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Solution
The correct option is B5 Given, mass of particle m=0.2kg Power=Work doneTime Interval ⇒P=Wt ∴Work done by external force on the particle in time interval of 5s W=P.t=0.5×5=2.5J
As mentioned in question, given force is the only external force acting on system.
So, from Work-energy theorem, Wext=ΔKE W=KEf−KEi=12mvf2−0 ⇒2.5=12×(0.2)×vf2 ∴vf=√25=5m/s