A particle of mass 0-6 g and having a charge of 25 nC is moving horizontally with a uniform velocity 1-2 -104 m-s in a uniform magnetic field- then the value of the magnetic induction is Take g-10 m-s2

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Standard XII

Physics

Analysis of Force Equation

A particle of...

Question

A particle of mass $0.6$ $g$ and having a charge of $25$ $n C$ is moving horizontally with a uniform velocity $1.2 \times 10^{4}$ $m / s$ in a uniform magnetic field, then the value of the magnetic induction is (Take $g = 10 m / s^{2}$ )

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10 T

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20 T

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200 T

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Solution

The correct option is A $20 T$
Particle is moving with uniform velocity therefore no force is acting on the particle.
So $m g - q v B = 0$
$0 \cdot 6 \times 10^{- 3} \times 10 = 25 \times 10^{- 9} \times 1 \cdot 2 \times 10^{4} \times B$
$B = 20 T$

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A particle of mass 0.6 g and having a charge of 25 nC is moving horizontally with a uniform velocity 1.2×104 m/s in a uniform magnetic field, then the value of the magnetic induction is (Take g=10 m/s2)

The correct option is A 20TParticle is moving with uniform velocity therefore no force is acting on the particle.So mg−qvB=00⋅6×10−3×10=25×10−9×1⋅2×104×BB=20T

A particle of mass $0.6$ $g$ and having a charge of $25$ $n C$ is moving horizontally with a uniform velocity $1.2 \times 10^{4}$ $m / s$ in a uniform magnetic field, then the value of the magnetic induction is (Take $g = 10 m / s^{2}$ )

The correct option is A $20 T$
Particle is moving with uniform velocity therefore no force is acting on the particle.
So $m g - q v B = 0$
$0 \cdot 6 \times 10^{- 3} \times 10 = 25 \times 10^{- 9} \times 1 \cdot 2 \times 10^{4} \times B$
$B = 20 T$