Question

A particle of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2$\times 10$${}^4$ ms${}^{-1}$ in a uniform magnetic field , then the value of the minimum magnetic inductionis (g = 10 ms${}^{-2}$)

• A. 0
• B. 10 T
• C. 20T
• D. 200T

Answer 1

Answer: (C)

20T

$m=0.6g=0.0006kg$

$q=25\times {10}^{-9}C$

$v=1.24m/s$

$g=10m/s^2$

$mg=Bqv$

$⟹\left(0.0006\right)\left(10\right)=B(25\times {10}^{-9})(1.2\times {10}^4)$

$⟹B=20T$