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Question

A particle of mass 1 Kg and carrying 0.01 C is at rest on an inclined plane of angle 30 with horizontal when an electric field of 4903NC1 applied parallel to horizontal, the coefficient of friction is


A
0.5
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B
13
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C
32
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D
37
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Solution

The correct option is C 37
Eq cos θ+f=mg sin θ
f=μN=mg sinθEq cos θ
μ[mg cos θ+Eq sin θ]=mg sinθEq cos θ
μ=mg sin θEq cos θmg cos θ+Eq sin θ
=1×9.8×124903×0.01×321×9.8×32+4903×0.01×12
=(9.84.9)12(9.8+4.93)32=4.9(21)4.9(2+13)3
μ=273=37

Physics

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