Question

A particle of mass $1$ kg has a velocity of $2$ m/s. A constant force of $2$ N acts on the particle for $1$s in a direction perpendicular to its initial velocity. Find the velocity and displacement of the particle at the end of $1$s.

Answer 1

$U_x=2m/s$

$U_y=0$

$a_x=0$

$a_y=\frac{2}{1}=2m/S^2$

after 1 sec

$V_x=U_x+a_{x}t$

$2+0=2m/s^2$

$V_y=U_y+a_{y}t$$2m/s^{}$

$V=\sqrt{V_x^2+V_y^2}=2\sqrt{2}m/s$

$S_x=u_{x}t+\frac{1}{2}{a}_x{t}^2$

2m

$S_y=u_{y}t+\frac{1}{2}{a}_y{t}^2$

$\frac{1}{2}\times 2\times 1=1m$

$\sqrt{S_x^2+S_y^2}$

$\sqrt{4+1}=\sqrt{5}$