Question

A particle of mass 1 kg is placed at a distance of 4 m from the centre and on the axis of a uniform ring of mass 5 kg and radius 3m. What is the work required to be done to increase the distance of the particle from 4m to 3$\sqrt{3m}$

• A. G/3
• B. G/2
• C. G/6
• D. G

Answer 1

The correct option is C

G/6

$U_1=-\frac{G\times 5\times 1}{5}J$ or $U_1=-GJ$

$U_1=\frac{G\times 5\times 1}{5}J=-\frac{5G}{6}J$ Work done = $-\left[\frac{5G}{6}\right]-[-G]=G-\frac{5G}{6}=\frac{G}{6}$.