A particle of mass $1 k g$ is projected with an initial velocity $10 m s^{- 1}$ at an angle of projection $45^{0}$ with the horizontal. The average torque acting on the projectile, between the time at which it is projected and the time at which it strikes the ground, about the point of projection in $N m$ is:

25

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50

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75

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100

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Solution

The correct option is B $50$
Range of projectile $R = \frac{u^{2} sin 2 θ}{g} = \frac{(10)^{2}}{10} = 10 m$
Average Torque $τ = m g \times \frac{R}{2} = 1 \times 10 \times \frac{10}{2} = 50 N m$

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A particle of mass 1kg is projected with an initial velocity 10ms−1 at an angle of projection 450 with the horizontal. The average torque acting on the projectile, between the time at which it is projected and the time at which it strikes the ground, about the point of projection in Nm is:

The correct option is B 50Range of projectile R=u2sin2θg=(10)210=10mAverage Torque τ=mg×R2=1×10×102=50Nm

The correct option is B $50$
Range of projectile $R = \frac{u^{2} sin 2 θ}{g} = \frac{(10)^{2}}{10} = 10 m$
Average Torque $τ = m g \times \frac{R}{2} = 1 \times 10 \times \frac{10}{2} = 50 N m$