CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass 1 kg is suspended by means of a string of length L=2 m. The string makes 6/π rps around a vertical axis through the fixed end. The tension in the string is

A
72 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
36 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
288 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 288 N
The tension is the centripetal force = mw2R
The angular velocity is w=(6/π)(2π)=12 rads/s
Substituting we get, Tension = 1×144×2=288N
Thus the correct options is (c)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon