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Question

A particle of mass 1 kg is suspended by means of a string of length L=2 m. The string makes 6/π rps around a vertical axis through the fixed end. The tension in the string is

A
72 N
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B
36 N
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C
288 N
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D
10 N
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Solution

The correct option is C 288 N
The tension is the centripetal force = mw2R
The angular velocity is w=(6/π)(2π)=12 rads/s
Substituting we get, Tension = 1×144×2=288N
Thus the correct options is (c)

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