A particle of mass 1 kg was sliding with a velocity of 10 ms−1 on a rough floor. It comes to rest after 5 s. The rate at which floor warms up is:
A particle of mass 1 kg was sliding with a velocity of 10 ms−1 on a rough floor. It comes to rest after 5 s. The rate at which floor warms up is:
The correct option is B 10 W
Given: mass, m=1 kg, velocity, v=10 ms−1, and time, t=5 s
The rate at which floor warms up is the rate at which friction does work. Due to friction between floor and particle, heat would be produced and the work done by friction would be dissipated as heat.
Frictional work, which will cause the moving body to come at rest, is equal to the initial kinetic energy of the body
Hence, frictional work =12×1×100=50 J
So, the rate at which floor warms up would be equal to the rate of frictional work 505=10 W.
Whole of the kinetic energy possessed by the body would be dissipated as heat due to the negative work done by friction.
Given: mass, m=1 kg, velocity, v=10 ms−1, and time, t=5 s
The rate at which floor warms up is the rate at which friction does work. Due to friction between floor and particle, heat would be produced and the work done by friction would be dissipated as heat.
Frictional work, which will cause the moving body to come at rest, is equal to the initial kinetic energy of the body
Hence, frictional work =12×1×100=50 J
So, the rate at which floor warms up would be equal to the rate of frictional work 505=10 W.
Whole of the kinetic energy possessed by the body would be dissipated as heat due to the negative work done by friction.
