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Question

A particle of mass 1 kg has velocity v1=(2t)^i and another particle of mass 2 kg has velocity v2=(t2)^j.

Columm IColumn II(a) Net force on centre of mass at 2 s(p) 209 unit(b) Velocity of centre of mass at 2 s(q) 68 unit(c) Displacement of centre of mass at 2 s(r) 803 unit(s) None

A
a-q, b-r, c-p
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B
a-r, b-q, c-p
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C
a-r, b-p, c-r
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D
a-r, b-p, c-r
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Solution

The correct option is A a-q, b-r, c-p
vc.m=2t^i+2t2^j3 ac.m=23^i+43t^j
F=ma=2^i+4t^j
F=4+64=68
Now at t=2 s,F=2^i+8^j
again at t=2 s,Vc.m=4^i+8^j3
Vc.c=803
also xcm=t23^i+29t3^j
at t=2 s,
xcm=43^i+169^j=43(^i+43^j)
dcm=43(1+169)=43×53=209

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