A particle of mass 1- 10-26 kg and charge 1-6- 10-19 C travelling with a velocity 1-28- 106 m-s along the positive X-axis enters a region in which a uniform electric field E- and a uniform magnetic field of induction B- are present- if E-102-4 - 103 k- NC-1 and B-8 - 10-2 - Wbm-2- the direction of motion of the particles is

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Byju's Answer

Standard XII

Physics

Properties of Field Lines

A particle of...

Question

A particle of mass $1 \times 10^{- 26} k g$ and charge $1.6 \times 10^{- 19} C$ travelling with a velocity $1.28 \times 10^{6} m / s$ along the positive $X$ -axis enters a region in which a uniform electric field $\to E$ and a uniform magnetic field of induction $\to B$ are present. if $\to E = - 102.4 \times 10^{3}^k N C^{- 1}$ and $\to B = 8 \times 10^{- 2}^j W b m^{- 2}$ , the direction of motion of the particles is

along the positive X-axis

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along the negative X-axis

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45^{O}

to the positive X-axis

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135^{O}

to the postive X-axis

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Solution

The correct option is B along the positive X-axis
Write Force
F = q(vXB) + qE.
F =0N.
Hence the particle will continue moving towards positive X-axis.

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\to E = - 102.4 \times 10^{3} k N C^{- 1}

and magnetic field

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The correct option is B along the positive X-axisWrite ForceF = q(vXB) + qE.F =0N.Hence the particle will continue moving towards positive X-axis.

The correct option is B along the positive X-axis
Write Force
F = q(vXB) + qE.
F =0N.
Hence the particle will continue moving towards positive X-axis.