A particle of mass 10-3kg and charge 5- C is thrown at a speed 20 m s-1 against a uniform electric field of strength 2- 105N C-1- How much distance will it travel before coming to rest momentarily-

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Standard XII

Physics

Potential Energy - External Viewpoint

A particle of...

Question

A particle of mass $10^{- 3} k g$ and charge $5 μ C$ is thrown at a speed $20 m s^{- 1}$ against a uniform electric field of strength $2 \times 10^{5} N C^{- 1}$ . How much distance will it travel before coming to rest momentarily?

0.1 m

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0.3 m

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0.05 m

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0.2 m

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Solution

The correct option is D $0.2 m$
Force on particle $= F = q E$ in opposite direction of motion

And, $F = m a = q E$

$⟹ a = \frac{q E}{m} = \frac{5 \times 10^{- 6} \times 2 \times 10^{5}}{10^{- 3}}$

$⟹ a = 10^{3} m / s^{2}$ and this acceleration is negative since particle is thrown against force.
And final velocity is $v = 0$

Using $v^{2} - u^{2} = 2 a s$

$⟹ 0 - 20^{2} = - 2 \times 1000 \times s$

$⟹ s = 0.2 m$

Answer-(D)

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A particle of mass 10−3kg and charge 5μC is thrown at a speed 20 m s−1 against a uniform electric field of strength 2×105N C−1. How much distance will it travel before coming to rest momentarily?

The correct option is D 0.2 mForce on particle=F=qE in opposite direction of motionAnd, F=ma=qE⟹a=qEm=5×10−6×2×10510−3⟹a=103m/s2 and this acceleration is negative since particle is thrown against force.And final velocity is v=0Using v2−u2=2as⟹0−202=−2×1000×s⟹s=0.2mAnswer-(D)

A particle of mass $10^{- 3} k g$ and charge $5 μ C$ is thrown at a speed $20 m s^{- 1}$ against a uniform electric field of strength $2 \times 10^{5} N C^{- 1}$ . How much distance will it travel before coming to rest momentarily?