A particle of mass $10 g m$ is describing $S . H . M$ along a straight line with period of $2 s e c$ and amplitude of $10 c m$ . Its kinetic energy when it is at $5 c m$ from its equilibrium position is

37.5 π^{2} e r g

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3.75 π^{2} e r g

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375 π^{2} e r g

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0.375 π^{2} e r g

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Solution

The correct option is C $375 π^{2} e r g$
Kinetic energy $K = \frac{1}{2} m ω^{2} (a^{2} - y^{2})$
$= \frac{1}{2} \times 10 \times {(\frac{2 π}{2})}^{2} [10^{2} - 5^{2}] = 375 π^{2} e r g$

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The correct option is C $375 π^{2} e r g$
Kinetic energy $K = \frac{1}{2} m ω^{2} (a^{2} - y^{2})$
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