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Question

# A particle of mass 100 g moving with a speed 1 m/s collides perfectly inelasticaly with another particle of mass 200 g initially at rest. Find the loss in the kinetic energy of the system due to collision.

A
0.066 J
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B
0.033 J
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C
0.33 J
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D
3.33 J
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Solution

## The correct option is B 0.033 JBefore collision After collision Using, law of conservation of momentum pi=pfm1u1+m2u2=(m1+m2)v 0.1×1=(0.1+0.2)v ⇒v=13 m/s ∴ Change in kinetic energy of system due to collision Δk.E = kf−ki =12(m1+m2)v2−12m1u21 =12×0.3×(13)2−12×0.1×12 =−0.033 J ∴ loss in kinetic energy of system due to collision is equal to 0.033 J

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