5y=12z+60 ... (1)
or 5dydt=12dzdt ... (2)
As v=5 m/s,
∴v2y+v2z=25
⇒25=(dydt)2+(dzdt)2
⇒25=14425(dzdt)2+(dzdt)2, from (2)
∴(dzdt)=2513
and so, dydt=2513×125=6013, from (2)
∴v=6013^j+2513^k
As z=10,
∴y=1805=36
i.e., P≡(0,36,10)
∴→L=→r×m→v
=(6013^j+2513^k)×13(36^j+10^k)
=∣∣
∣
∣∣^i^j^k0602503610∣∣
∣
∣∣=−^i(900−600)=−300^i
∴∣∣∣→L∣∣∣=300