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Byju's Answer
Standard VIII
Physics
Normal Force
A particle of...
Question
A particle of mass
1
g
having velocity
(
3
^
i
−
2
^
j
)
has a glued impact with another particle of
mass
2
g
and velocity
(
4
^
i
+
6
^
k
)
. Magnitude of velocity of the formed particle is
A
5.46
m
s
−
1
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B
0
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C
6.44
m
s
−
1
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D
4.64
m
s
−
1
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Solution
The correct option is
A
5.46
m
s
−
1
The linear momentum should be conserved so
m
1
V
1
+
m
2
V
2
=
(
m
1
+
m
2
)
V
or
1
(
3
^
i
−
2
^
j
)
+
2
(
4
^
i
+
6
^
k
)
=
(
1
+
2
)
V
so the velocity of formed particle will be
V
=
1
3
(
11
^
i
−
2
^
j
+
12
^
k
)
whose magnitude is
V
=
1
3
√
121
+
4
+
144
=
5.46
m
/
s
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0
Similar questions
Q.
A particle of mass
1
g
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v
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i
−
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Q.
A particle of mass
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Q.
A particle of mass
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3
^
i
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^
j
)
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−
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collides with another body of
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Q.
A particle of mass
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kg
has velocity
→
v
1
=
(
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^
i
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2
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has velocity
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v
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Column I
Column II
(a)
Net force on centre of mass at 2 s
(p)
20
9
unit
(b)
Velocity of centre of mass at 2 s
(q)
√
68
unit
(c)
Displacement of centre of mass in 2 s
(r)
√
80
3
unit
(s)
None
Q.
Two particles of equal mass have coordinates
(
2
m
,
4
m
,
6
m
)
and
(
6
m
,
2
m
,
8
m
)
. Of these one particle has a velocity
→
v
1
=
(
2
^
i
)
m/s
and another particle has velocity
→
v
2
=
(
2
^
j
)
m/s
at time
t
=
0
. The coordinate of their centre of mass at time
t
=
1
s
will be
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