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Question

A particle of mass 1g having velocity (3^i2^j) has a glued impact with another particle of

mass 2g and velocity (4^i+6^k). Magnitude of velocity of the formed particle is

A
5.46 ms1
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B
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C
6.44 ms1
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D
4.64 ms1
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Solution

The correct option is A 5.46 ms1
The linear momentum should be conserved so m1V1+m2V2=(m1+m2)V
or 1(3^i2^j)+2(4^i+6^k)=(1+2)V
so the velocity of formed particle will be V=13(11^i2^j+12^k)
whose magnitude is V=13121+4+144=5.46m/s

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