A particle of mass $2 k g$ is moving in circular path with constant speed $20 m / s$ . The magnitude of change in velocity when particle travels from $A$ to $P$ will be:

20 \sqrt{2} m / s

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40 m / s

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40 \sqrt{2} m / s

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Solution

The correct option is A $20 \sqrt{2} m / s$
R.E.F image
$△ ¯ v = {¯ v}_{P} - {¯ v}_{A} = {¯ v}_{P} + (- {¯ v}_{A})$
$| △ ¯ v | =$ length of diagonal
$= \sqrt{v^{2} + v^{2}} = v \sqrt{2}$
Ans : A

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A particle of mass 2 kg is moving in circular path with constant speed 20 m/s. The magnitude of change in velocity when particle travels from A to P will be:

The correct option is A 20√2m/sR.E.F image △¯v=¯vP−¯vA=¯vP+(−¯vA)|△¯v|= length of diagonal =√v2+v2=v√2Ans : A

A particle of mass $2 k g$ is moving in circular path with constant speed $20 m / s$ . The magnitude of change in velocity when particle travels from $A$ to $P$ will be:

The correct option is A $20 \sqrt{2} m / s$
R.E.F image
$△ ¯ v = {¯ v}_{P} - {¯ v}_{A} = {¯ v}_{P} + (- {¯ v}_{A})$
$| △ ¯ v | =$ length of diagonal
$= \sqrt{v^{2} + v^{2}} = v \sqrt{2}$
Ans : A