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Question
A particle of mass 2kg is moving such that at time t, its position vector, in meter, is given by →r=5^i−2t2^j. The angular momentum of the particle at t=2s about origin in kgm2s−1 is:
A particle of mass 2kg is moving such that at time t, its position vector, in meter, is given by →r=5^i−2t2^j. The angular momentum of the particle at t=2s about origin in kgm2s−1 is:
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Solution
The correct option is B −80^k
→P=m→v=md→rdt=2(−4t)^j=−16^j putting t=2
→r=5^i−8^j
→L= →r x →p
Substituting,
→L= (5^i−8^j) x (−16^j)
→L=−80^k
→P=m→v=md→rdt=2(−4t)^j=−16^j putting t=2
→r=5^i−8^j
→L= →r x →p
Substituting,
→L= (5^i−8^j) x (−16^j)
→L=−80^k
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