A particle of mass 2 kg moves in simple harmonic motion and its potential energy U varies with position x as shown. The period of oscillation of the particle is:
A
2π5 s
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B
2√2π5 s
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C
√2π5 s
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D
4π5 s
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Solution
The correct option is D4π5 s 12kA2=1.0 12k(0.4)2=1.0 or k=12.5 or 252 N/m T=2π√mk=2π
⎷2252=4π5 s