A particle of mass 2 kg moves with an initial velocity of 4 -2 - ms -1 on the x-y plane- A force F -2 -8 - N acts on the particle- The initial position of the particle is 2 m - 3 m - Then for y -3 m-A- Possible value of x is only x-2 mB- Possible value of x is not only x-2 m- but there exists some other value of x alsoC- Time taken is 2 sD- All of the above

A particle of mass 2 kg moves with an initial velocity of $\to v = 4^i + 4^j m s^{- 1}$ . A constant force of $\to F = - 20^j N$ is applies on the particle. Initially, the particle was at (0,0). The x-cordinate of the particle when its y-coordinate again becomes zero is given by

Q. A particle of mass

2 kg

initially at origin

(0, 0)

moves with an initial velocity

\to V = 4^i + 4^j m/s

. If a constant force

\to F = - 20^j N

is applied on the particle, the

x -

coordinate of the particle when its

y -

coordinate again becomes zero is

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A particle of mass 2 kg moves with an initial velocity of (4^i+2^j)ms−1 on the x-y plane. A force →F=(2^i−8^j) N acts on the particle. The initial position of the particle is (2 m,3 m). Then for y=3m,

A particle of mass 2 kg moves with an initial velocity of $(4^i + 2^j) m s^{- 1}$ on the x-y plane. A force $\to F = (2^i - 8^j)$ N acts on the particle. The initial position of the particle is (2 m,3 m). Then for y=3m,