A particle of mass $2 k g$ performing of SHM and its potential energy function is given as $U = 4 x^{2} - 20 x .$ If maximum potential energy is $75 J$ then:
Position of the particle when it is at its positive extreme -

x = 7.5

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x = 12.5

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x = 2.5

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N o n e

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Solution

The correct option is B $x = 7.5$
Given :A particle of mass 2 kg performing of SHM and its potential energy function is given as $U = 4 x^{2} - 20 x$ . If maximum potential energy is 75 J then:
Position of the particle when it is at its positive extreme -

Solution :
Potential energy is maximum at extreme points so $U = 4 x^{2} - 20 x$ = 75J

$4 x^{2} - 20 x - 75 = 0$ $\Rightarrow$ $(2 x - 15) (2 x + 5)$

Values of x are (-2.5 , 7.5 )
Positive extreme is at x=7.5

The Correct Opt = A

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