A particle of mass 2kg is moving in xy plane under the action of a force. Its velocity and acceleration at a certain instant of time are given by →v=(3^i+4^j)m/s and →a=(5^i+4^j)m/s2. Find the power delivered by the force at that instant of time.
A
60W
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B
62W
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C
64W
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D
66W
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Solution
The correct option is B62W Given:
Mass of particle, m=2kg
Instantaneous velocity, →v=(3^i+4^j)m/s
Instantaneous acceleration, →a=(5^i+4^j)m/s2
We know that the instantaneous power of a force is given by, P=→F.→v ⇒P=m→a.→v ⇒P=2×(5^i+4^j).(3^i+4^j) ⇒P=30+32=62W