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Question

A particle of mass 2 kg is moving with a uniform speed of 10 m/s in xy plane along the line x=6 m. Find the magnitude of the angular momentum of the particle about the origin.

A
0 kg-m2/sec
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B
60 kg-m2/sec
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C
120 kg-m2/sec
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D
20 kg-m2/sec
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Solution

The correct option is C 120 kg-m2/sec

Angular momentum of particle having mass (m) is given by L=m(r×v)
or L=mvr1
where, r1 is the perpendicular distance from origin to path.
Here, r1 will remain same, so angular momentum of the particle will be constant.
We have, r1=6 m, m=2 kg, v=10 m/s
So, L=mvr1=2×10×6=120 kg-m2/sec
Magnitude of the angular momentum is 120 kg-m2/sec

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