A particle of mass 2kg moves with an initial velocity of (4^i+2^j)ms−1 on the x - y plane. A force →F=(2^i−8^j)N acts on the particle. The initial position of the particle is (2,3)m. Then when particle reaches y=3m,
A
Possible value of x is only x=2m
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B
Possible value of x is not only x=2m, but there exists some other value of x also
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C
Time taken is 2s
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D
All of the above
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Solution
The correct option is B Possible value of x is not only x=2m, but there exists some other value of x also →u=4^i+2^j→a=→Fm=^i−4^j Let at any time, the coordinates be (x,y) x−2=uxt+12axt2 ⇒x−2=4t+12t2y−3=2t−124t2 ⇒y−3=2t−2t2 When y=3m,t=0sand1s; When t=0,x=2m When t=1s,x=6.5m