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Question

A particle of mass 2 kg moving with a velocity of 3 m/s is acted upon by a force which changes its direction of motion by an angle of 90 without changing its speed. What is the magnitude of impulse experienced by the particle?


A
6 N-s
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B
2 N-s
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C
32 N-s
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D
62 N-s
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Solution

The correct option is D 62 N-s
Given m=2 kg is the mass of the particle.
Let initial momentum p1=mv1 ^i
p1=2×3^i=6^i
Final momentum p2=mv2 ^j
p2=2×3^j=6^j
From impulse-momentum theorem:
J=m Δv=Δp
=p2p1
=6^j6^i

Thus, magnitude of impulse experienced by the particle is:
|J|=62+62=62 N-s

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