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Standard XII

Physics

Spring Block's Time Period

A particle of...

Question

A particle of mass $200 g$ executes simple harmonic motion. The restoring force is provided by a spring of spring constant $80 {Nm}^{- 1}$ . What would be the time period?

0.93 s

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0.62 s

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0.31 s

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None of these

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Solution

The correct option is C $0.31 s$
Given, mass of particle $(m) = 200 g = 0.2 kg$
Spring constant $(K) = 80 N/m$
Time period of oscillation $(T) = 2 π \sqrt{\frac{m}{K}}$
$= 2 \times 3.14 \times \sqrt{\frac{0.2}{80}}$
$= 0.314 s$

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Spring Block's Time Period

Standard XII Physics

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A particle of mass 200 g executes simple harmonic motion. The restoring force is provided by a spring of spring constant 80 Nm−1. What would be the time period?

The correct option is C 0.31 sGiven, mass of particle (m)=200 g=0.2 kg Spring constant (K)=80 N/m Time period of oscillation (T)=2π√mK =2×3.14×√0.280 =0.314 s

A particle of mass $200 g$ executes simple harmonic motion. The restoring force is provided by a spring of spring constant $80 {Nm}^{- 1}$ . What would be the time period?

The correct option is C $0.31 s$
Given, mass of particle $(m) = 200 g = 0.2 kg$
Spring constant $(K) = 80 N/m$
Time period of oscillation $(T) = 2 π \sqrt{\frac{m}{K}}$
$= 2 \times 3.14 \times \sqrt{\frac{0.2}{80}}$
$= 0.314 s$