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Byju's Answer
Standard VI
Physics
Work Done
A particle of...
Question
A particle of mass
2
k
g
moves under the action of a constant force
→
F
=
(
5
^
i
−
2
^
j
)
N
. If its displacement is
6
^
i
m
, Find the work done by the force
→
F
?
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Solution
The force acting on the body is
→
F
=
(
5
^
i
−
2
^
j
)
N
while the displacement
x
=
6
^
i
m
.
The work done
=
→
F
.
→
x
=
(
5
^
i
−
2
^
j
)
6
^
i
=
30
J
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