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Question

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.


A

7.9J

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B

3.5 × 103J

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C

7.9× 103J

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D

35J

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Solution

The correct option is C

7.9× 103J


The total mechanical energy of the system is

E=12mω2A2

=12m(2πT)2A2=2π2mA2T2

=2π2(40×105kg)(2.0×102m)2(0.20s)2

7.9×103J.


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