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Standard XII

Physics

The Circular Motion

A particle of...

Question

A particle of mass in and charge Q moving with velocity v enters a region of uniform magnetic field of induction B. Its path in the region is

Straight line

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Circular, it

v \times B = 0

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Circular, if

v . B = 0

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Parabolic

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Solution

The correct option is C Circular, if $v . B = 0$
When v is perpendicular to B, path is circular, hence $v \cdot B = 0$ .

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A particle of mass in and charge Q moving with velocity v enters a region of uniform magnetic field of induction B. Its path in the region is

The correct option is C Circular, if v.B=0When v is perpendicular to B, path is circular, hence v⋅B=0.

The correct option is C Circular, if $v . B = 0$
When v is perpendicular to B, path is circular, hence $v \cdot B = 0$ .