You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Examples

A particle of...

Question

A particle of mass $m_{1}$ and moving with velocity $v_{1}$ collides head on with another stationary particle of mass $m_{2}$ elastically. If after the collision their velocities are $v_{1}$ and $v_{2}$ then under the condition $m_{1} = m_{2}$ their values will be :

v_{1} = 0, v_{2} = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{1} = u_{1}, v_{2} = u_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{1} = 0, v_{2} = u_{1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v_{2} = 0, v_{1} = u_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $v_{1} = 0, v_{2} = u_{1}$
In elastic head-on collision for masses ( $m_{1} = m_{2}$ ) with one of the mass at rest the velocities before collision get interchanged after collision. Hence, here after collision, $v_{1} = 0$ and $v_{2} = u_{1}$ .

Suggest Corrections

Similar questions

Q. Particle

A

of mass

m_{1}

moving with velocity

(\sqrt{3}^i +^j) m s^{- 1}

collides with another partice

B

of mass

m_{2}

which is at rest initially. Let

_{1}

and

_{2}

be the velocities of particles

A

and

B

after collision respectively. If

m_{1} = 2 m_{2}

and after collision

_{1} = (^i + \sqrt{3}^j) m s^{- 1},

the angle between

_{1}

and

_{2}

is :

Q. Two bodies of masses

m_{1}

and

m_{2}

moving on the same direction with velocities

u_{1}

and

u_{2}

collide. The velocities after collision are

v_{1}

and

v_{2}

. If each sphere loses the same amount of kinetic energy, then

If two masses m₁ and m₂ collide with each other. Before the collision, the velocities are u₁ and u₂ respectively. After the collision the velocities are V₁ and V₂. What is the final momentum after collision?

Q. Two balls of masses

m_{1} and m_{2}

such that (

m_{2} >> m_{1}

) are moving with initial velocities

v_{1} and v_{2}

respectively towards each other. The final velocity of

m_{2}

after collision will be [Assume collision to be perfectly elastic]

Q. Two particles of masses

m_{1}, m_{2}

move with initial velocities

u_{1}

and

u_{2}

. On collision, one of the particles get excited to higher level, after absorbing energy

ϵ

. If final velocities of particles be

v_{1}

and

v_{2}

then we must have

Join BYJU'S Learning Program

A particle of mass m1 and moving with velocity v1 collides head on with another stationary particle of mass m2elastically. If after the collision their velocities are v1 and v2 then under the condition m1=m2 their values will be :

The correct option is C v1=0,v2=u1In elastic head-on collision for masses (m1=m2) with one of the mass at rest the velocities before collision get interchanged after collision. Hence, here after collision, v1=0 and v2=u1.

A particle of mass $m_{1}$ and moving with velocity $v_{1}$ collides head on with another stationary particle of mass $m_{2}$ elastically. If after the collision their velocities are $v_{1}$ and $v_{2}$ then under the condition $m_{1} = m_{2}$ their values will be :

The correct option is C $v_{1} = 0, v_{2} = u_{1}$
In elastic head-on collision for masses ( $m_{1} = m_{2}$ ) with one of the mass at rest the velocities before collision get interchanged after collision. Hence, here after collision, $v_{1} = 0$ and $v_{2} = u_{1}$ .