Question

A particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$. Both of them the same momentum but their different kinetic energies are $E_1$ and $E_2$ respectively. If $m_1>m_2$ then-

• A. $E_1<E_2$
• B. $\frac{E_1}{E_2}=\frac{m_1}{m_2}$
• C. $E_1>E_2$
• D. $E_1=E_2$

Answer 1

The correct option is A $E_1<E_2$

$E=\frac{p^2}{2m}$
$p=constant$
$\Rightarrow E\propto \frac{1}{m}\Rightarrow$ if $m_1>m_2\Rightarrow E_2>E_1$