A particle of mass $m_{1}$ moving with velocity v collides with a mass $m_{2}$ at rest, then they get embedded. Just after collision, velocity of the system :

increases

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decreases

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remains constant

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becomes zero

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Solution

The correct option is B decreases
Applying conservation of momentum,
$m_{1} v + m_{2} (0) = (m_{1} + m_{2}) v_{1} \Rightarrow v_{1} = \frac{m_{1}}{(m_{1} + m_{2})} v$
as $m_{1} < (m_{1} + m_{2})$
Therefore, velocity decreases.

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A particle of mass m1 moving with velocity v collides with a mass m2 at rest, then they get embedded. Just after collision, velocity of the system :

The correct option is B decreasesApplying conservation of momentum,m1v+m2(0)=(m1+m2)v1⇒v1=m1(m1+m2)vas m1<(m1+m2) Therefore, velocity decreases.

A particle of mass $m_{1}$ moving with velocity v collides with a mass $m_{2}$ at rest, then they get embedded. Just after collision, velocity of the system :

The correct option is B decreases
Applying conservation of momentum,
$m_{1} v + m_{2} (0) = (m_{1} + m_{2}) v_{1} \Rightarrow v_{1} = \frac{m_{1}}{(m_{1} + m_{2})} v$
as $m_{1} < (m_{1} + m_{2})$
Therefore, velocity decreases.