1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A particle of mass m1 moving with velocity v in a positive direction collides elastically with a mass m2 moving in opposite direction also at velocity v. If m2 >> m1, then :

A
the velocity of m1 immediately after collision is nearly 3v
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
the change in momentum of m1 is nearly 4m1v
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
the change in kinetic energy of m1 is nearly 4mv2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
all of the above
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D all of the aboveLet the velocity of mass m1 after the collision be v1 in positive direction.Given : u1=v uu=−v e=1 m2>>m1Using v1=(m1−em2)u1+(1+e)m2u2m1+m2 v1=(m1−(1)m2)v+(1+1)m2(−v)m1+m2=m1v−3m2vm1+m2For m2>>m1 ⟹v1=−3v (-ve sign represents m1 recoils)Now change in momentum ΔP=m1v2−m1vΔP=m1(−3v)−m1v=−4m1v ⟹|ΔP|=4m1vChange in kinetic energy of m1 ΔE=12m1v21−12m1v2 ΔE=12m1(3v)2−12m1v2=4m1v2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program