A particle of mass m - 2 kg starts moving on a straight line y - 2 with a constant velocity 10- m-s- Its angular momentum about origin L- for the path from point A to point B

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Angular Momentum

A particle of...

Question

A particle of mass $m = 2 kg$ starts moving on a straight line $y = 2$ with a constant velocity $10^i m/s$ . Its angular momentum about origin $(\to L)$ for the path from point $A$ to point $B$

Continuously decreases

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Continuously increases

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Remains constant

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First increases and then decreases.

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Solution

The correct option is C Remains constant
As we know, $\to L = m v r_{⊥}$
While moving from $A$ to $B$ , the perpendicular distance of line of velocity from the origin always remains constant (equals to $2 units)$ .
$r_{⊥}$ = constant
Hence, $\to L$ = constant
Angular momentum remains constant.

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Angular Momentum

Standard XIII Physics

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A particle of mass m=2 kg starts moving on a straight line y=2 with a constant velocity 10^i m/s. Its angular momentum about origin (→L) for the path from point A to point B

The correct option is C Remains constantAs we know, →L=mvr⊥ While moving from A to B, the perpendicular distance of line of velocity from the origin always remains constant (equals to 2 units). r⊥ = constant Hence, →L = constant Angular momentum remains constant.

A particle of mass $m = 2 kg$ starts moving on a straight line $y = 2$ with a constant velocity $10^i m/s$ . Its angular momentum about origin $(\to L)$ for the path from point $A$ to point $B$

The correct option is C Remains constant
As we know, $\to L = m v r_{⊥}$
While moving from $A$ to $B$ , the perpendicular distance of line of velocity from the origin always remains constant (equals to $2 units)$ .
$r_{⊥}$ = constant
Hence, $\to L$ = constant
Angular momentum remains constant.