wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass m=5 kg is moving with a uniform speed 32 m/s in XY plane along the line y=x+4. The angular momentum about the origin is
[in kg m2/s]

A
40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
60
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 60

Given,
Mass of particle m=5 kg
Speed of particle v=32 m/s
As we know, L=mvr
where r is the shortest /perpendicular distance, of the particle from the origin.
As we know,
Perpendicular distance between a point and a line is given by,
r=Ax1+Bx2+CA2+B2=∣ ∣ ∣xy+412+(1)2∣ ∣ ∣=00+42
(substituting (x,y)=(0,0) for origin)
r=22

Therefore, from L=mvr
L=5×32×22
L=60 kg m2/s

flag
Suggest Corrections
thumbs-up
56
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon