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Question

A particle of mass m=5 kg is moving with a uniform speed 32 m/s in XY plane along the line y=x+4. The angular momentum about the origin is
[in kg m2/s]

A
40
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B
60
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C
zero
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D
20
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Solution

The correct option is B 60

Given,
Mass of particle m=5 kg
Speed of particle v=32 m/s
As we know, L=mvr
where r is the shortest /perpendicular distance, of the particle from the origin.
As we know,
Perpendicular distance between a point and a line is given by,
r=Ax1+Bx2+CA2+B2=∣ ∣ ∣xy+412+(1)2∣ ∣ ∣=00+42
(substituting (x,y)=(0,0) for origin)
r=22

Therefore, from L=mvr
L=5×32×22
L=60 kg m2/s

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