A particle of mass m and charge +q enters a region of magnetic field with a velocity v, as shown in fig.
If the particle enters at E, if the intercept EF is $X \times R c o s θ$ . Find X

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Solution

Since the angle between a vertical and a line is equal to the angle between horizontal and line perpendicular to the previous line, the angle between center of circle, point E and point O is $θ$ .
Hence distance $E O = R c o s θ$
$⟹ E F = 2 R c o s θ$

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A particle of mass m and charge +q enters a region of magnetic field with a velocity v, as shown in fig.If the particle enters at E, if the intercept EF is X×Rcosθ. Find X

Since the angle between a vertical and a line is equal to the angle between horizontal and line perpendicular to the previous line, the angle between center of circle, point E and point O is θ.Hence distance EO=Rcosθ⟹EF=2Rcosθ

A particle of mass m and charge +q enters a region of magnetic field with a velocity v, as shown in fig.
If the particle enters at E, if the intercept EF is $X \times R c o s θ$ . Find X

Since the angle between a vertical and a line is equal to the angle between horizontal and line perpendicular to the previous line, the angle between center of circle, point E and point O is $θ$ .
Hence distance $E O = R c o s θ$
$⟹ E F = 2 R c o s θ$